-x^2+10x-41=0

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Solution for -x^2+10x-41=0 equation:


Simplifying
-1x2 + 10x + -41 = 0

Reorder the terms:
-41 + 10x + -1x2 = 0

Solving
-41 + 10x + -1x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
41 + -10x + x2 = 0

Move the constant term to the right:

Add '-41' to each side of the equation.
41 + -10x + -41 + x2 = 0 + -41

Reorder the terms:
41 + -41 + -10x + x2 = 0 + -41

Combine like terms: 41 + -41 = 0
0 + -10x + x2 = 0 + -41
-10x + x2 = 0 + -41

Combine like terms: 0 + -41 = -41
-10x + x2 = -41

The x term is -10x.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10x + 25 + x2 = -41 + 25

Reorder the terms:
25 + -10x + x2 = -41 + 25

Combine like terms: -41 + 25 = -16
25 + -10x + x2 = -16

Factor a perfect square on the left side:
(x + -5)(x + -5) = -16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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